Dear Uncle Colin,

I have a little problem. You see, there’s this bird, A, in its nest at time t=0 - the nest is at (20,17) - and it travels with a velocity of 6i+7j (in the appropriate units). But there’s another bird, B, whose nest is at (8,9) and who travels at pi+2pj. Then when t=4, it turns out that B is (get this) south-west of bird A! For\ some reason, I have to figure out the speed of bird B. How would you do it?

- Help Evaluating Right Ornithology Numbers

Hi, HERON, and thanks for your message!

Ah, a classical two-bird problem with vectors. Luckily, we have quite a lot of information and it should fall apart fairly quickly.

A picture

Before doing anything else, I’d draw a picture of what’s going on.

I did that. I also plotted it in Desmos:

Where are the birds?

We can write the position vectors of the birds as rA=(206t)i+(17+7t)j and rB=(8+pt)i+(9+2pt)j.

Better than that, we’re only really interested in the situation when t=4, so we can substitute that in: rA=4i+11j, which corresponds to the picture, and rB=(8+4p)i+(9+8p)j.

Vector BA

If B is southwest of A, vector BA is in the northwesterly direction: it’s a multiple of i+j.

But we can work out BA=rArB, which is ((4)(8+4p))i+(11(9+8p))j.

More clearly, that’s (44p)i+(28p)j, which needs to be in the form ki+kj - or rather, the components must be equal.

So 44p=28p, giving 2=4p and p=12.

Finally the speed

B’s speed is p2+(2p2), or |p|5, which is 125 of those appropriate units.

Hope that helps!

- Uncle Colin